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That means the output has a Laplace transform of $$\frac{1}{s(1+sRC)}$$ The inverse is \$1-e^{-t/RC}\$ which starts from zero as you would expect. The impulse is just a infinitesimal mathematical construct and so shouldn't be expected to adhere to physical laws. This chapter begins with the definition of the impulse response, that is, the response of a circuit that is subjected to the excitation of the impulse function. ... this text will help you learn or review the basics of Laplace and Z-transforms, the FFT, state variables, and much more. ... Compute the impulse response of the series RC circuit of. 4.20 IMPULSE RESPONSE OF SERIES R–L CIRCUIT. Fig. 4.24 shows a series R–L circuit. The circuit is excited RL by an impulse function of magnitude E at time t = 0. Using KVL, we have, The Laplace transform of Eq. (4.92) is given below. If the circuit is initially relaxed i.e, i (0−) = 0, Eq. (4.93) can be written as.

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